TN 12th MathsLearn · Visualize · Practice

Chapter 5

Two Dimensional Analytical Geometry-II

Circles, conics, parametric forms, tangents & normals and real-life applications.

1. What is a conic?

Slice a double cone with a plane and the curve of the cut is a conic section. Tilt the plane and you move smoothly between a circle, an ellipse, a parabola, and a hyperbola. Remarkably, all four are captured by a single focus–directrix definition.

DefinitionFocus–directrix definition

A conic is the set of points PP whose distance to a fixed point (the focus FF) and a fixed line (the directrix) are in a constant ratio ee, called the eccentricity: PFPM=e\dfrac{PF}{PM} = e, where PMPM is the perpendicular distance from PP to the directrix.

A single second-degree equation Ax2+Bxy+Cy2+Dx+Ey+F=0Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 describes every conic. At this level we work with B=0B = 0 (no xyxy term), so the axes stay parallel to the coordinate axes.

2. Eccentricity decides the shape

That single number ee determines which of the four conics you get. It is the most important quantity in the chapter — most 'identify the conic' questions come straight from it.

  • e=0e = 0 → circle
  • 0<e<10 < e < 1 → ellipse
  • e=1e = 1 → parabola
  • e>1e > 1 → hyperbola

You can read the type straight off the general equation without completing the square:

  • A=CA = C (and no xyxy term) → circle.
  • B=0B = 0 and exactly one of A,CA, C is zero → parabola.
  • ACA \ne C but A,CA, C have the same sign → ellipse.
  • A,CA, C have opposite signs → hyperbola.
Example
Identify the conic: (a) 16y2=4x2+6416y^2 = -4x^2 + 64, (b) x2y2=x+3x^2 - y^2 = x + 3, (c) 4x29y216x+18y=294x^2 - 9y^2 - 16x + 18y = 29.
Key idea: In the Visualize tab, switch between the four conics and watch $e$, the foci, the directrix and the latus rectum all move together — the same object, deformed.

3. Circle — standard and general form

A circle is the locus of a point that stays a fixed distance rr from a fixed centre. There is no elongation, so e=0e = 0.

Centre at origin
x2+y2=r2x^2 + y^2 = r^2
Centre (h, k)
(xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2

Expanding the centre–radius form gives the general form. Compare it carefully — this is the workhorse identity of the whole circle section:

General form
x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0
  • Centre (g,f)(-g, -f)
  • Radius r=g2+f2cr = \sqrt{g^2 + f^2 - c}
  • Real circle if g2+f2c>0g^2 + f^2 - c > 0; a single point if =0=0; no real locus if <0<0
Note: An equation is a circle only when the coefficients of $x^2$ and $y^2$ are equal and there is no $xy$ term. If they differ, divide through first so both become $1$ before you read off $g$ and $f$.
Example
Find the general equation of the circle with centre (3,4)(-3, -4) and radius 33.
ExampleCompleting the square
Find the centre and radius of x2+y24x+6y12=0x^2 + y^2 - 4x + 6y - 12 = 0.

4. Circle — diameter form and position of a point

If you know the two endpoints of a diameter, you never need to find the centre and radius separately — this compact form gives the circle at once.

DefinitionDiameter form

If (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the ends of a diameter, the circle is (xx1)(xx2)+(yy1)(yy2)=0(x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0.

Example
Find the circle whose diameter joins (4,2)(-4, -2) and (1,1)(1, 1).
ExampleLine meets the axes
The line 3x+4y12=03x + 4y - 12 = 0 meets the axes at AA and BB. Find the circle on ABAB as diameter.
DefinitionPosition of a point (Theorem 5.3)

Substitute P(x1,y1)P(x_1, y_1) into the general form. Then PP is outside, on, or inside the circle according as x12+y12+2gx1+2fy1+cx_1^2 + y_1^2 + 2gx_1 + 2fy_1 + c is >0> 0, =0= 0, or <0< 0.

Example
Where does (2,3)(2, 3) lie relative to x2+y26x8y+12=0x^2 + y^2 - 6x - 8y + 12 = 0?

5. Parabola — the four standard orientations

Every point of a parabola is equidistant from the focus and the directrix, so e=1e = 1. The vertex sits halfway between them. There are four standard parabolas with vertex at the origin, one for each direction of opening.

Vertex at the origin, focal distance a > 0
  • y2=4axy^2 = 4ax — opens right; focus (a,0)(a,0), directrix x=ax = -a, axis the xx-axis.
  • y2=4axy^2 = -4ax — opens left; focus (a,0)(-a,0), directrix x=ax = a.
  • x2=4ayx^2 = 4ay — opens up; focus (0,a)(0,a), directrix y=ay = -a, axis the yy-axis.
  • x2=4ayx^2 = -4ay — opens down; focus (0,a)(0,-a), directrix y=ay = a.
DefinitionLatus rectum

The latus rectum is the focal chord perpendicular to the axis. For every standard parabola its length is 4a4a — and its endpoints are exactly 2a2a above and below the focus. It fixes how 'wide' the parabola is at the focus.

Example
For y2=12xy^2 = 12x, find the vertex, focus, directrix and latus rectum.
ExampleBuilding the equation from focus & directrix
Find the parabola with focus (2,0)(-2, 0) and directrix x=2x = 2.
ExampleShifted vertex
Find the vertex, focus, directrix and latus rectum of x24x5y1=0x^2 - 4x - 5y - 1 = 0.

6. Ellipse — foci, vertices, directrices, latus rectum

An ellipse is the set of points whose distances to two foci add to a constant 2a2a. It looks like a stretched circle with 0<e<10 < e < 1.

a > b, major axis along x
x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1
  • c=a2b2c = \sqrt{a^2 - b^2} (minus sign), foci (±c,0)(\pm c, 0)
  • Eccentricity e=ca<1e = \dfrac{c}{a} < 1
  • Vertices (±a,0)(\pm a, 0); ends of minor axis (0,±b)(0, \pm b)
  • Directrices x=±aex = \pm\dfrac{a}{e}
  • Length of latus rectum =2b2a= \dfrac{2b^2}{a}
Note: If the larger denominator is under $y^2$ instead, the major axis is vertical: swap the roles, so foci become $(0, \pm c)$ and directrices $y = \pm\tfrac{a}{e}$. Always let $a$ be the larger semi-axis.
Example
Find the foci and eccentricity of x225+y29=1\dfrac{x^2}{25} + \dfrac{y^2}{9} = 1.
ExampleFrom foci and vertices
Find the ellipse with foci (±2,0)(\pm 2, 0) and vertices (±3,0)(\pm 3, 0).
ExampleCompleting the square
For 4x2+y2+24x2y+21=04x^2 + y^2 + 24x - 2y + 21 = 0, find the centre, vertices and foci.

7. Hyperbola — foci, asymptotes, directrices

A hyperbola is the set of points whose distances to two foci differ by a constant 2a2a. It has two branches and a pair of straight-line asymptotes it hugs at infinity; here e>1e > 1.

Transverse axis along x
x2a2y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1
  • c=a2+b2c = \sqrt{a^2 + b^2} (plus sign), foci (±c,0)(\pm c, 0)
  • Eccentricity e=ca>1e = \dfrac{c}{a} > 1, equivalently e=1+b2a2e = \sqrt{1 + \tfrac{b^2}{a^2}}
  • Vertices (±a,0)(\pm a, 0); transverse axis length 2a2a, conjugate axis 2b2b
  • Asymptotes y=±baxy = \pm\dfrac{b}{a}x
  • Directrices x=±aex = \pm\dfrac{a}{e}; latus rectum =2b2a= \dfrac{2b^2}{a}
Note: The only algebraic difference from the ellipse is the minus sign — and it flips $c = \sqrt{a^2 - b^2}$ into $c = \sqrt{a^2 + b^2}$, pushing the foci outside the curve. Note also that here $a$ is the number under the positive term, whether or not it is the larger.
Example
Find the vertices and foci of 9x216y2=1449x^2 - 16y^2 = 144.
ExampleTransverse axis on the y-axis
Find the hyperbola with vertices (0,±4)(0, \pm 4) and foci (0,±6)(0, \pm 6).
ExampleCompleting the square
Find the centre, foci and eccentricity of 11x225y244x50y256=011x^2 - 25y^2 - 44x - 50y - 256 = 0.

8. Parametric forms

Instead of a relation between xx and yy, a single parameter can generate every point of a conic. Parametric points make tangent and locus problems much cleaner — one variable instead of two.

  • Circle x2+y2=a2x^2 + y^2 = a^2:  (acosθ, asinθ)\ (a\cos\theta,\ a\sin\theta)
  • Parabola y2=4axy^2 = 4ax:  (at2, 2at)\ (at^2,\ 2at)
  • Ellipse x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1:  (acosθ, bsinθ)\ (a\cos\theta,\ b\sin\theta)
  • Hyperbola x2a2y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1:  (asecθ, btanθ)\ (a\sec\theta,\ b\tan\theta)
Note: For the ellipse, $\theta$ (the eccentric angle) is the angle at the centre to the corresponding point on the auxiliary circle $x^2+y^2=a^2$ — not the angle to the point on the ellipse itself.
Example
Verify that (acosθ,bsinθ)(a\cos\theta, b\sin\theta) lies on x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1.

9. Tangents and normals to conics

A tangent touches the curve at exactly one point; the normal is perpendicular to it through the same point. For the parabola y2=4axy^2 = 4ax the tangent at (x1,y1)(x_1, y_1) has a neat replacement rule (replace y2y^2 by yy1yy_1 and 2x2x by x+x1x + x_1):

Parabola tangent at (x₁, y₁)
yy1=2a(x+x1)yy_1 = 2a(x + x_1)
Parabola y² = 4ax, point (at², 2at)
  • Tangent (parametric): ty=x+at2ty = x + at^2
  • Normal (parametric): y+tx=2at+at3y + tx = 2at + at^3

For the ellipse and hyperbola the slope form is the exam favourite — memorise the sign difference (the only change is +b2+b^2 vs b2-b^2):

Ellipse tangent of slope m
y=mx±a2m2+b2y = mx \pm \sqrt{a^2 m^2 + b^2}
Hyperbola tangent of slope m
y=mx±a2m2b2y = mx \pm \sqrt{a^2 m^2 - b^2}
ExampleTangent & normal to a parabola
Find the tangent and normal to x2+6x+4y+5=0x^2 + 6x + 4y + 5 = 0 at (1,3)(1, -3).

10. Condition of tangency

When does the line y=mx+cy = mx + c just touch a conic? Substituting and forcing the resulting quadratic to have equal roots gives a single condition linking cc to the slope mm. These are heavily tested.

  • Parabola y2=4axy^2 = 4ax: tangent is y=mx+amy = mx + \dfrac{a}{m}, i.e. c=amc = \dfrac{a}{m}; point of contact (am2,2am)\left(\dfrac{a}{m^2}, \dfrac{2a}{m}\right).
  • Ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1: condition c2=a2m2+b2c^2 = a^2 m^2 + b^2.
  • Hyperbola x2a2y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1: condition c2=a2m2b2c^2 = a^2 m^2 - b^2.
Example
For what cc is y=2x+cy = 2x + c a tangent to x216+y29=1\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1?
Watch out: Two tangents can be drawn to any conic from an external point. The locus of points from which the two tangents are perpendicular is the directrix for a parabola, and the director circle $x^2 + y^2 = a^2 \pm b^2$ for an ellipse ($+$) or hyperbola ($-$).

11. Real-life conics

The reflective properties of conics power much of the technology around you. A ray from the focus of a parabola reflects out parallel to the axis (and vice-versa); a ray from one focus of an ellipse or hyperbola reflects to the other focus.

  • Parabola — headlight and satellite-dish reflectors, solar heating troughs, suspension-bridge cables, and projectile paths.
  • Ellipse — planetary orbits (Kepler: the Sun sits at one focus), whispering galleries, and the lithotripter that shatters kidney stones with waves focused from one focus to the other.
  • Hyperbola — cooling-tower profiles, long-range LORAN navigation from time differences, and the paths of some comets.
ExampleSuspension-bridge / parabolic arch
A parabolic arch is 15 m15\text{ m} high at the centre and 40 m40\text{ m} wide at the base. Find its equation with the vertex at the origin.
ExampleOrbit — distance between foci
Earth's maximum and minimum distances from the Sun are 152×106152 \times 10^6 km and 94.5×10694.5 \times 10^6 km. The Sun is at one focus. Find the distance between the two foci.
ExampleWhispering gallery (ellipse)
An elliptical ceiling is 34 m34\text{ m} long and 8 m8\text{ m} high at the centre. Where are the foci?