TN 12th MathsLearn · Visualize · Practice

Chapter 2

Complex Numbers

The imaginary unit, Argand plane, modulus & argument, polar/Euler form and De Moivre's theorem.

1. Why complex numbers?

Some equations simply have no real solution. The equation x2+1=0x^2 + 1 = 0 asks for a number whose square is 1-1 — and no real number squares to a negative value. To solve such equations we extend the number system beyond the real line.

DefinitionImaginary unit

The imaginary unit ii is defined by i=1i = \sqrt{-1}, so that i2=1i^2 = -1.

Powers of ii cycle with period 4 — memorise this and large powers become instant:

i1=i,i2=1,i3=i,i4=1,i5=i, i^1 = i,\quad i^2 = -1,\quad i^3 = -i,\quad i^4 = 1,\quad i^5 = i,\ \dots
Example
Simplify i50i^{50}.
Example
Evaluate i15+i16+i17+i18i^{15} + i^{16} + i^{17} + i^{18}.

2. What is a complex number?

DefinitionComplex number

A complex number has the form z=a+biz = a + bi with a,ba, b real. Here a=Re(z)a = \operatorname{Re}(z) is the real part and b=Im(z)b = \operatorname{Im}(z) is the imaginary part.

Two complex numbers are equal only when their real parts match AND their imaginary parts match. Addition and multiplication follow ordinary algebra with the single rule i2=1i^2 = -1:

(a+bi)+(c+di)=(a+c)+(b+d)i(a+bi) + (c+di) = (a+c) + (b+d)i
(a+bi)(c+di)=(acbd)+(ad+bc)i(a+bi)(c+di) = (ac - bd) + (ad + bc)i
Example
Multiply (2+3i)(14i)(2 + 3i)(1 - 4i).
Example
Find real x,yx, y if (x+yi)+(23i)=5+i(x + yi) + (2 - 3i) = 5 + i.

3. The Argand plane

Every complex number z=a+biz = a + bi is the point (a,b)(a, b): the horizontal axis carries the real part, the vertical axis the imaginary part. This picture — the Argand plane — turns algebra into geometry.

Key idea: Addition of complex numbers is vector addition of their points; multiplication scales and rotates. Open the Visualize tab and drag the point to feel this.

4. Conjugate and division

DefinitionConjugate

The conjugate of z=a+biz = a + bi is zˉ=abi\bar z = a - bi — the reflection of zz across the real axis.

The conjugate is the key tool for division and for extracting parts:

zzˉ=a2+b2=z2,Re(z)=z+zˉ2,Im(z)=zzˉ2iz\bar z = a^2 + b^2 = |z|^2,\qquad \operatorname{Re}(z) = \tfrac{z + \bar z}{2},\qquad \operatorname{Im}(z) = \tfrac{z - \bar z}{2i}
Example
Write 12+i\dfrac{1}{2 + i} in the form a+bia + bi.
Example
Express 3+i1i\dfrac{3+i}{1-i} in the form a+bia+bi.

5. Modulus of a complex number

The modulus measures the distance of zz from the origin — the hypotenuse of the right triangle with legs xx and yy.

DefinitionModulus (Definition 2.4)

If z=x+iyz = x + iy, then z=x2+y2|z| = \sqrt{x^2 + y^2}.

Properties of the modulus
  • z=zˉ|z| = |\bar z| and zzˉ=z2z\bar z = |z|^2
  • z1z2=z1z2|z_1 z_2| = |z_1||z_2|
  • z1z2=z1z2, z20\left|\dfrac{z_1}{z_2}\right| = \dfrac{|z_1|}{|z_2|},\ z_2 \ne 0
  • z1+z2z1+z2|z_1 + z_2| \le |z_1| + |z_2| (triangle inequality)
  • zn=zn|z^n| = |z|^n for integer nn
Example
Find (3+4i)(1+i)|(3+4i)(1+i)|.

6. Square root of a complex number

To find a+bi\sqrt{a+bi}, set it equal to x+yix+yi, square, and match parts. A clean shortcut uses the modulus.

a+bi=±(z+a2+isgn(b)za2)\sqrt{a+bi} = \pm\left(\sqrt{\tfrac{|z|+a}{2}} + i\,\operatorname{sgn}(b)\sqrt{\tfrac{|z|-a}{2}}\right)
Example
Find 68i\sqrt{6 - 8i}.
Note: Always check by squaring your answer — a $30$-second verification that catches sign slips: $(2\sqrt2 - \sqrt2 i)^2 = 8 - 8i + 2i^2 = 6 - 8i$. ✓

7. Polar (trigonometric) form and argument

A non-zero complex number is fixed by how far it is from the origin (modulus rr) and the direction it points (angle θ\theta). With x=rcosθx = r\cos\theta and y=rsinθy = r\sin\theta:

DefinitionPolar form (Definition 2.6)

z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta), where r=zr = |z| and θ=arg(z)\theta = \arg(z) satisfies tanθ=yx\tan\theta = \dfrac{y}{x} (chosen for the correct quadrant).

Note: The argument is only fixed up to multiples of $2\pi$. The unique value in $(-\pi,\pi]$ is the principal argument $\operatorname{Arg}(z)$.

In polar form, multiplication and division become rotations — angles add or subtract:

z1z2=r1r2[cos(θ1+θ2)+isin(θ1+θ2)]z_1 z_2 = r_1 r_2\big[\cos(\theta_1+\theta_2) + i\sin(\theta_1+\theta_2)\big]
Example
Express z=1+iz = 1 + i in polar form.
Example
Where is z=1+iz = -1 + i? Give its polar form.

8. Geometry and locus

Because z1z2|z_1 - z_2| is the distance between two points, equations in zz describe familiar shapes. This is a favourite exam theme.

  • zz0=r|z - z_0| = r is a circle of radius rr centred at z0z_0.
  • za=zb|z - a| = |z - b| is the perpendicular bisector of the segment joining aa and bb.
  • zz1+zz2=k|z - z_1| + |z - z_2| = k is an ellipse with foci z1,z2z_1, z_2.
Example
Describe the locus of z(2+3i)=4|z - (2 + 3i)| = 4.

9. Euler's form

Euler's formula packs the polar form into an exponential, which makes powers and roots especially clean:

eiθ=cosθ+isinθz=reiθe^{i\theta} = \cos\theta + i\sin\theta \qquad\Longrightarrow\qquad z = r\,e^{i\theta}

Multiplying multiplies the moduli and adds the angles: r1eiθ1r2eiθ2=r1r2ei(θ1+θ2)r_1 e^{i\theta_1}\cdot r_2 e^{i\theta_2} = r_1 r_2\, e^{i(\theta_1 + \theta_2)}. Setting θ=π\theta=\pi gives the famous eiπ=1e^{i\pi} = -1.

10. De Moivre's theorem and roots

DefinitionDe Moivre's theorem

For any integer nn, (cosθ+isinθ)n=cosnθ+isinnθ\big(\cos\theta + i\sin\theta\big)^n = \cos n\theta + i\sin n\theta.

Example
Compute (cosπ6+isinπ6)6\left(\cos\tfrac{\pi}{6} + i\sin\tfrac{\pi}{6}\right)^{6}.

Run in reverse, De Moivre gives the nn distinct nn-th roots, equally spaced by 360n\tfrac{360^\circ}{n} around a circle:

zk=cos2πkn+isin2πkn,k=0,1,,n1z_k = \cos\tfrac{2\pi k}{n} + i\sin\tfrac{2\pi k}{n},\quad k = 0, 1, \dots, n-1
Example
Find the cube roots of unity and their sum.
Key idea: Explore the roots wheel in the Visualize tab — change $n$ and watch the roots redistribute evenly.